I agree with yuma. This is a representation of murder and mayhem, right? No half-wins.
I think of a shared victory as a truce between the bad guys. So they both win. But no half-wins.
You see, the thing I'm scared about is what almost happened at the end of WWTWDP: Yuma the SK was like "Hey mafia, let's have a truce and kill off mail-mi and nkirbit and win together!" I don't want that to happen. But I don't want town to win, and I don't want it to be "Everyone loses!". I think I'll do something with the flavor names.
That is a valid concern. If you think about it generally each faction has a 33% chance of winning. What ashersky and I are suggesting basically gives fire and ice a ~35% chance each and town only a 30% chance. percentages are just kinda made up there. But if you allow town to win that would give town a 36% chance and fire and ice only 32% each. So I guess there has to be some give and take.
So many the question is thus: who has the advantage if things are left alone. Does town really have a 33% chance of winning? Or is it actually closer to 40%. If so, giving scum the change to win together might even things out... Or does town have more like a 30% chance. Then maybe town needs a buff to compensate for mafia's chance to win together?
Make sense?
Or maybe the best route to go is the 0.5 win.
Ideally it won't matter, but there is a chance it might.
whaaaat? no. You know your percentages are off because they add up to 100%. If two wins can be awarded, that means that the percentages will not add up to 100, they will be over 100.
In the situation with 1 town, 1 fire, 1 ice:
- If scum can both win if they are the only ones left: town wins 25%, fire wins 50%, ice wins 50%. It is 25% over 100 because there is a 25% chance that both scum shoot the townie. Explanation: scum loses if they are shot, win if they are not shot as long as they shoot somebody. They don't care who they shoot so they do so randomly. 25% chance they shoot each other and town wins, 25% chance they both shoot the townie and both win, 50% chance one shoots the other and the other shoots the townie.
- If scum tie if they are the only ones left: town wins 100% of the time. Scum lose if they are shot. If they are not shot, they win by shooting other scum. So that's what they both do, town wins.
That's my issue with letting scum both win.
Mail-mi's solution is awesome though. Not sure if I like it better than a tie, but it certainly works:
- Same scenario, let's say that if only two scum left fire beats ice (I assume this will be known info because flavor will be provided with flips).
fire loses if they are shot, wins if they are not shot, so they shoot randomly. ice lose if they are shot, win if they are not shot and they shoot fire. So they shoot fire. 50% ice wins, 50% town wins, 0% fire wins.-----------------------------------------------------------------------------------------
while I was typing that I realized a couple (pretty important) things
- Yuma was probably talking about winning percentages from the start of D1, not the scenario with 1 town, 1 fire, 1 ice. In any case, the percentages should still be over 100, though less than 25% over.
- I am assuming that it is known who the townie is... that changes everything if this is not the case.