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[mith]

Watno (50-10^(1-10^137), 50-10^(1-10^137))   

You mean 50-10^137, dont you?

No, that would be well outside the range.

Watno submitted "50-10^-99999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999" for each of his coordinates. (-9...[lotsmore9s]...9 = 1-10^137)

[mith]

(Apparently the answer to the challenge problem is a little bit better than 1 in a hundred million. That's assuming a uniform random distribution of the points, which obviously isn't the case in this game, but I suspect a weighted distribution symmetrical about the origin would give a similar answer.)

I briefly thoght about this.  Not only is it really rare, but I think those calculations would be insane.  I couldn't do them, and I think about probability for a living.

I have an idea how to approach this, but I cheated and googled the result: Valtr 1994

[Watno]

I meant 50-10^-137.  There's still one 10^too much in your version,  I think.

[Axxle]

I guess you're better off picking positive numbers because other people are more likely to pick positive numbers because other people are more likely to pick positive numbers.

That was my idea when picking my coordinates.

[Tables]

I had figured that the line (x,x) was the best chance of winning, as people were more likely to select positive numbers. I just underestimated how big some people would go. I hadn't expected them to be above 15,15.

[Axxle]

I realized that most people would pick positive coordinates (or at least assume that others would pick positive coordinates).  I figured that we might see one person max in each of the other quadrants.

Thus, I was trying to pick the winning score, and wanted to pick the point on the line x=y that has that magnitude.  I thought 55 would be tops.  Now i feel like calculating how far out I could have pushed that point on the same line and still been within Watno's point.

(50-10^(1-10^136), 50-10^(1-10^136))   would be close.  (watno's point is on the x=y line)

[Jorbles]

That was really interesting. I clearly didn't think it through very much when I entered, but I would totally play again.

[Schneau]

Wooo, I won! Total luck, especially considering there were only 2 other points in the II quadrant.

The thing I find most interesting is that almost all of the points besides yuma's were near y=x or y=-x.

Someone could have come close to winning by playing (0,58).

[mith]

I meant 50-10^-137.  There's still one 10^too much in your version,  I think.

What you meant and what you submitted are two different things, apparently. My shorter version is equivalent to what you submitted.