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[Titandrake]

Oh sure, I need a minor distraction.

[Grujah]

Oh sure, I need a minor distraction.

Beat you to it I guess, just entered couple've minutes ago

[mith]

Convex Hull:
Watno (50-10^(1-10^137), 50-10^(1-10^137))   
Kuildeous (-73.4, 72.8)   
SwitchedFromStarcraft (-33, -33)   
yuma (0, -46)

Scores:
59.05: Schneau (-52.113, 27.77767)
55: shraeye (55/sqrt(2), 55/sqrt(2))
37.54: Axxle (28, 25)
35.33: Dsell (24.98, 24.98)
24.76: Young Nick (-18, 17)
16.97: Tables (12, 12)
6.28: Titandrake (0, 2pi)
6.08: cayvie (6, -1)
4.15: Jimmmmm (e, pi)
1.41: Jorbles (1, -1)
0: Galzria (0, 0)

Congrats, Schneau!

[Insomniac]

LOL Galz why did you pick 0,0 it's guaranteed to lose.

[Watno]

It's not.

At least i didnt kingmake^^

[mith]

It's guaranteed to not lose, but score 0. If every other point were on the convex hull, he would have won.

[Axxle]

LOL Galz why did you pick 0,0 it's guaranteed to lose.

Unless everyone else is on the hull.
edit: ninja'd!

[mith]

Challenge problem: What is the probability that 14 randomly selected points in the given range would be on the convex hull?

[eHalcyon]

It's not.

At least i didnt kingmake^^

When it was at 14/15 I contemplated submitting 99,99 or something ridiculous.  But I thought that wouldn't be fair to people actually trying.

[shraeye]

It's not.

At least i didnt kingmake^^

HAha, i LOOVE your coordinates!

Also, FoS to Kuildeous for picking such big numbers and letting Schneau win

[Galzria]

I also might've misread and thought the closest to origin won - which is why I thought people would end up with the same coordinates.

[Young Nick]

I figured it would be somewhat similar to the classic 2/3 of the average game. So I put something a bit less than that figuring people here would be smart/geeky/nerdy/mathematically-inclined enough to have heard of it.

Shucks.

[mith]

(Apparently the answer to the challenge problem is a little bit better than 1 in a hundred million. That's assuming a uniform random distribution of the points, which obviously isn't the case in this game, but I suspect a weighted distribution symmetrical about the origin would give a similar answer.)

[shraeye]

(Apparently the answer to the challenge problem is a little bit better than 1 in a hundred million. That's assuming a uniform random distribution of the points, which obviously isn't the case in this game, but I suspect a weighted distribution symmetrical about the origin would give a similar answer.)

I briefly thoght about this.  Not only is it really rare, but I think those calculations would be insane.  I couldn't do them, and I think about probability for a living.

[Grujah]

It's guaranteed to not lose, but score 0. If every other point were on the convex hull, he would have won.

but if 0,0 is on hull, it loses.

[Insomniac]

It's guaranteed to not lose, but score 0. If every other point were on the convex hull, he would have won.

but if 0,0 is on hull, it loses.

Everyone pick points in the same quadrant!

[SwitchedFromStarcraft]

The thing I am most surprised about is that no one else entered with two negative numbers.

[Jimmmmm]

I guess you're better off picking positive numbers because other people are more likely to pick positive numbers because other people are more likely to pick positive numbers.

[shraeye]

I realized that most people would pick positive coordinates (or at least assume that others would pick positive coordinates).  I figured that we might see one person max in each of the other quadrants.

Thus, I was trying to pick the winning score, and wanted to pick the point on the line x=y that has that magnitude.  I thought 55 would be tops.  Now i feel like calculating how far out I could have pushed that point on the same line and still been within Watno's point.

[Galzria]

If I were to hazard a guess now, based on the personalities of the people of this forum, it would be that the majority of our Convex Hull will reside in they (-X, Y) quadrant. I'm willing to bet that we dip below the X-Axis though as well - but by how much I'm not sure.

Or we could have all simply picked the same point, in which case we'll all lose.

[shraeye]

I guess you're better off picking positive numbers because other people are more likely to pick positive numbers because other people are more likely to pick positive numbers.

exactly

[Grujah]

I entered (late) 25,20. Wouldn't do much.

[Watno]

Watno (50-10^(1-10^137), 50-10^(1-10^137))   

You mean 50-10^137, dont you?

[Jimmmmm]

Thus, I was trying to pick the winning score, and wanted to pick the point on the line x=y that has that magnitude.  I thought 55 would be tops.  Now i feel like calculating how far out I could have pushed that point on the same line and still been within Watno's point.

Anywhere in the 60s would have done it I think.

[shraeye]

Thus, I was trying to pick the winning score, and wanted to pick the point on the line x=y that has that magnitude.  I thought 55 would be tops.  Now i feel like calculating how far out I could have pushed that point on the same line and still been within Watno's point.

Anywhere in the 60s would have done it I think.

Well only right up to watno's point, as his was also on that line.  As was Tables' and Galzria's.