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« on: March 08, 2012, 09:05:17 pm »
In a 3 player Dominion game, the turn order is Player A, followed by Player B, followed by Player C
Player A plays KC possession so is entitled to 3 possession turns. On the first possession turn, player A forces player B to play KC possession. After that turn ends, but before Player B gets his normal turn, 5 additional possession turns need to be played:
-2 more turns in which A possesses B
-3 turns in which B possesses C
What is the order of these 5 turns? I think the answer is that A gets his two possession turns and only then does B get his 3 possession turns, but wasn't sure so wanted to get confirmation.