hmm, this seems less informative than it did when i set out. basically there's a lot of symmetry mathematically. Joth has 3 on wagon and is voting for one wagon member; frisk has 3 on and is voting for one of them.
Due to this, everybody (except eevee who could hammer with any partner) has 4 scumteam possibilities that could hammer (this includes possibilities where one scumpartner is voting for the other even though they're at 3), and 4 that can't (barring voting for themselves). So there's not much to be gained. I admit that this was a bit too early for me to march off to find scumteams.
For completeness (since i saidthey'd be coming) here are the results.
these teams can hammer: arch/ash, arch/eevee, arch/frisk, arch/robz, ash/eevee, ash/frisk, ash/robz, eev/frisk, eev/insom, eev/jo, eev/robz, eev/shray, eev/sfs, frisk/robz, insom/jo, insom/shray, insom/sfs, jo/shray, jo/sfs, shray/sfs
These teams can't hammer: arch/insom, arch/jo, arch/shray, arch/sfs, ash/insom, ash/jo, ash/shray, ash/sfs, frisk/insom, frisk/jo, frisk/shray, frisk/sfs, insom/robz, jo/robz, robz/shray, robz/sfs
This research shows no objective results unless we are willing to submit our own biases. I didn't want to add my biases to this post (obviously, as I'm leaving even myself in for completeness) because there are people who I wouldn't be surprised if I couldn't convince to believe me. I had hoped that this would get more unbiased results.