Here's a nice binary choice for us.
If we believe that (5 scum, 2 something else, PPS) was the starting setup, then chairs is guaranteed scum, by my results.
If we believe that (3 scum, 2 something else, PPS) was the starting setup, then chairs is guaranteed town.
What about (5 scum, 1 something else, PPS)? That's not possible? I thought earlier results indicated that.
I have to be honest, I'm not checking your problem solving at all. It all confuses me to no end.
Also, godfathers. And stuff. Couldn't something like that falsely incriminate chairs? Not against a Chairs lynch. Just trying to help solve without actually having to do math.
Bolded part: That is impossible. I'm fairly certain I never thought that it WAS possible, but I don't remember.
In any case, remember that my results have changed now - see a few posts ago where I said that faust has made an error with my results.
So I've done everything again. My level of confidence is higher now, since I've actually got a computer to check things rather than doing it in my head.
Fair enough not checking my problem solving. It's complicated. But I'm quite certain. (assuming that my results are now, finally, correct)
Rereading #1618 might help to clarify things for you? I'm fairly certain that what I lay out there is correct.
Then further analysis narrows us down to the two options I talk about in the quoted post.
Godfathers are absolutely an option which could make things wrong, but all it can do is ADD one scum to the total, consistently across all nights. So the options are still the only possible options - just keep in mind that there might also be a "Red person" who is not town.