Before checking...
I have W0 | B2 | B3 | B4 | G5.
EFHW has a total of 28 and a | b | c sum is 10, therefore d | e sum is 18, which can only be B9 | W9.
c | d is consecutive but different colours, so must have ? | ? | W8 | B9 | W9.
a | b sum is therefore 2, and b | c are same colour, leaving B0 | W2 | W8 | B9 | W9 or B1 | W1 | W8 | B9 | W9.
fang's c | d are the same colour. They can't be 5G as I have one. e can't be 5G as there is no X | Y | X | X combination less than 5. a can't be 5G as a | b | c would sum to at least 17.
If b is 5G then a and c must sum to 10. c can't be 7 as that would require a higher W, so it must be 4W | 5G | 6W | 7W | 8B, but the difference between the e and the a is only 4, so b can't be 5G, so we have all B and W.
Only two B so it must be W | B | W | W | B. But that doesn't work because the first B must be at least 6, and there's no W higher than 7.
So something somewhere has gone wrong it seems.