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Author Topic: Easy Puzzles  (Read 808407 times)

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florrat

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Re: Easy Puzzles
« Reply #400 on: July 17, 2013, 07:38:17 pm »
+3

You can get 3 peddlers by the end of turn 2 in a solitaire game.

Open 5C.
Turn 1: Spend coin token, buy Stonemason and gain 2 Nomad Camps to top of deck. Draw them with Necropolis and 2C.
Turn 2: Play everything to get 6 coins, 3 buys, and peddlers down to a cost of 2. Buy 3 Peddlers (or a Peddler and a Stonemason).
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scott_pilgrim

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Re: Easy Puzzles
« Reply #401 on: July 17, 2013, 07:41:14 pm »
0

You can get 3 peddlers by the end of turn 2 in a solitaire game.

Open 5C.
Turn 1: Spend coin token, buy Stonemason and gain 2 Nomad Camps to top of deck. Draw them with Necropolis and 2C.
Turn 2: Play everything to get 6 coins, 3 buys, and peddlers down to a cost of 2. Buy 3 Peddlers (or a Peddler and a Stonemason).

Wow, very nice!
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Simon (DK)

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Re: Easy Puzzles
« Reply #402 on: July 17, 2013, 08:09:31 pm »
+8

Here's another simple one: Get 2 peddlers by (the end of) turn 2.

Baker in kingdom. Shelters. Open 4/3.

Turn 1: Buy Nomad Camp
Turn 2: Play Necropolis, Nomad Camp, (Peddlers cost 4), play 3 Coppers + 1 coin, buy a Stonemason, overpaying 4.
Yep, I was wondering if there might be another way but I doubt it.

Player 1 buys Noble Brigand, revealing Overgrown Estate and Hovel from each of Players 2, 3, and 4. (You're Player 4.)

Player 2 buys Stonemason + 2 Masquerades, draws Necropolis/Copper/Copper/shuffle/Masquerade/Masquerade.

Player 3 buys Stonemason + 2 Market Squares, draws Necropolis/Copper/Copper/shuffle/Market Square/Market Square.

Player 4 (you) buys Stonemason + 2 Squires, draws Necropolis/Copper/Copper/Squire/Squire.


Player 1

Player 2 plays Necropolis/Masquerade/Masquerade. You get both Market Squares from Player 3 for Coppers.

Player 3

Player 4 (you) plays Necropolis/Market Square/Market Square/Squire/Squire (for buys). Play 2 Copper. Buy 2 Stonemason, gaining 4 Peddlers. Buy 5 more Peddlers.


Can you get all 10? I can't.  :(

I can:

Baker (or Black Market including Baker), Noble Brigand, Stonemason, Masquerade, Border Village, Talisman, Squire and Peddler in the kingdom.


Turn 1:

Player 1 buys Noble Brigand.

Player 2 buys Stonemason and gains 2 Masquerades.

Player 3 buys Border Village and gains Talisman.

Player 4 (you) buys Stonemason and gains 2 Squires


Turn 2:

(your hand: Necropolis, Squire, Squire, junk, junk)

Player 1

Player 2 plays Necropolis and 2 Masquerades. You pass the 2 junk cards and receive Border Village and Talisman.

Player 3

Player 4 (you) plays Necropolis, Border Village, Squire (for buys), Squire (for buys) and Talisman.
Peddler costs 0$, you have 5 buys, and for each of the buys you gain a copy from Talisman = 10 Peddlers.
« Last Edit: July 17, 2013, 08:26:09 pm by Simon (DK) »
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SirPeebles

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Re: Easy Puzzles
« Reply #403 on: July 17, 2013, 08:20:35 pm »
+2

Damn it, Player 3!  WTF?  I call shenanigans.
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AdamH

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Re: Easy Puzzles
« Reply #404 on: July 18, 2013, 09:23:48 am »
0

You can get 3 peddlers by the end of turn 2 in a solitaire game.

Open 5C.
Turn 1: Spend coin token, buy Stonemason and gain 2 Nomad Camps to top of deck. Draw them with Necropolis and 2C.
Turn 2: Play everything to get 6 coins, 3 buys, and peddlers down to a cost of 2. Buy 3 Peddlers (or a Peddler and a Stonemason).

When you play the two Stonemasons, don't you have to trash the other two copper in your hand so that you only have $4?
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Warfreak2

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Re: Easy Puzzles
« Reply #405 on: July 18, 2013, 09:35:07 am »
0

You don't draw the Stonemasons.
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AdamH

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Re: Easy Puzzles
« Reply #406 on: July 18, 2013, 09:37:57 am »
0

ugh. I'm so good at this  :-X  ::)  :o  >:(  :-[
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Warfreak2

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Re: Easy Puzzles
« Reply #407 on: July 18, 2013, 09:40:41 am »
0

In fact, you don't even have multiple Stonemasons.
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yed

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Re: Easy Puzzles
« Reply #408 on: September 05, 2013, 03:36:24 am »
0

Maybe too easy:
You lost Duchy split 1-7. At the end of the game your Dukes are worth 3 points. How is that possible?
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Davio

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Re: Easy Puzzles
« Reply #409 on: September 05, 2013, 04:28:54 am »
0

You're playing a game with more than 2 players, so there are 4 more Duchies! ;D

But there are ways to steal them from your opponent, Masquerade/Ambassador (with Possession), Graverobber/Rogue.
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yed

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Re: Easy Puzzles
« Reply #410 on: September 05, 2013, 04:48:43 am »
+1

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Re: Easy Puzzles
« Reply #411 on: September 05, 2013, 06:15:23 am »
0

You're playing a game with more than 2 players, so there are 4 more Duchies! ;D
If that was the correct answer, it wouldn't be an easy puzzle.
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florrat

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Re: Easy Puzzles
« Reply #412 on: September 05, 2013, 10:53:38 am »
+3

Maybe too easy:
You lost Duchy split 1-7. At the end of the game your Dukes are worth 3 points. How is that possible?
Two technically correct answers:
-You have no Dukes (so all of them are worth 3 points)
-You have 1 Duke, which also exactly increases the value of your 2 Silk Road, so in some sense, the Duke is worth 3 points.
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eHalcyon

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Re: Easy Puzzles
« Reply #413 on: September 05, 2013, 11:49:15 am »
+1

Maybe too easy:
You lost Duchy split 1-7. At the end of the game your Dukes are worth 3 points. How is that possible?
Two technically correct answers:
-You have no Dukes (so all of them are worth 3 points)
-You have 1 Duke, which also exactly increases the value of your 2 Silk Road, so in some sense, the Duke is worth 3 points.

Neither is technically correct.  If you have no Dukes, your Dukes are not worth anything.  If you have 1 Duke and 2 SR, the Duke itself would still be worth X equal to the number of Duchies you have; the increase in value of SR is the worth of the SR, not the Duke.

A technically correct answer would be -- you have 3 Dukes.  With 1 Duchy, 3 Dukes are worth 3 points.  (The question did not say that the Dukes were worth 3 points each.)
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SirPeebles

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Re: Easy Puzzles
« Reply #414 on: September 05, 2013, 11:58:07 am »
+9

If you have no Dukes, then it is true that each of your Dukes is worth 3 points.  It is also true that each of your Dukes is worth 17 points.
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Witherweaver

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Re: Easy Puzzles
« Reply #415 on: September 05, 2013, 03:20:42 pm »
+1

You've been vacuoused!
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Grujah

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Re: Easy Puzzles
« Reply #416 on: September 05, 2013, 07:34:26 pm »
0

Maybe too easy:
You lost Duchy split 1-7. At the end of the game your Dukes are worth 3 points. How is that possible?

He later Ambassador'd 2 Duchies back to you. (or, you Saboteur'd+ Rouge'd him)
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ashersky

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Re: Easy Puzzles
« Reply #417 on: September 05, 2013, 08:18:17 pm »
+3

Maybe too easy:
You lost Duchy split 1-7. At the end of the game your Dukes are worth 3 points. How is that possible?

To me, this statement means that, at the end of the game, when everyone counts up their cards, I have 1 Duchy in my deck and my opponent has 7.

"Losing the split" means I got 1 and he got 7.  If I later stole 2 Duchies with Possession/Ambassador, or Rogue, or whatever, I didn't lose the split 1/7.  I lost the split 3/5.

The correct answer has to be "I had 3 Dukes worth 1 VP each, so my "Dukes" were worth 3."
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Aidan Millow

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Re: Easy Puzzles
« Reply #418 on: September 05, 2013, 09:34:45 pm »
0

Maybe too easy:
You lost Duchy split 1-7. At the end of the game your Dukes are worth 3 points. How is that possible?
Two technically correct answers:
-You have no Dukes (so all of them are worth 3 points)
-You have 1 Duke, which also exactly increases the value of your 2 Silk Road, so in some sense, the Duke is worth 3 points.

Neither is technically correct.  If you have no Dukes, your Dukes are not worth anything.  If you have 1 Duke and 2 SR, the Duke itself would still be worth X equal to the number of Duchies you have; the increase in value of SR is the worth of the SR, not the Duke.

A technically correct answer would be -- you have 3 Dukes.  With 1 Duchy, 3 Dukes are worth 3 points.  (The question did not say that the Dukes were worth 3 points each.)

The first one can work, depending on your definition of  "your dukes are worth 3 points," if taken to mean "if a duke is in your deck, it is worth 3 points"  then if you don't have any dukes in your deck you have a contradiction and can derive anything.

Edit: Ninja'd (and I really shouldn't be surprised).
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sudgy

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Re: Easy Puzzles
« Reply #419 on: September 05, 2013, 09:53:07 pm »
0

Another way to say it is that your duchies are worth three points...
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   Quote from: sudgy on June 31, 2011, 11:47:46 pm

eHalcyon

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Re: Easy Puzzles
« Reply #420 on: September 05, 2013, 10:34:14 pm »
0

Maybe too easy:
You lost Duchy split 1-7. At the end of the game your Dukes are worth 3 points. How is that possible?
Two technically correct answers:
-You have no Dukes (so all of them are worth 3 points)
-You have 1 Duke, which also exactly increases the value of your 2 Silk Road, so in some sense, the Duke is worth 3 points.

Neither is technically correct.  If you have no Dukes, your Dukes are not worth anything.  If you have 1 Duke and 2 SR, the Duke itself would still be worth X equal to the number of Duchies you have; the increase in value of SR is the worth of the SR, not the Duke.

A technically correct answer would be -- you have 3 Dukes.  With 1 Duchy, 3 Dukes are worth 3 points.  (The question did not say that the Dukes were worth 3 points each.)

The first one can work, depending on your definition of  "your dukes are worth 3 points," if taken to mean "if a duke is in your deck, it is worth 3 points"  then if you don't have any dukes in your deck you have a contradiction and can derive anything.

Edit: Ninja'd (and I really shouldn't be surprised).

I understand the logic involved, but the value of Dukes are clearly defined.
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scott_pilgrim

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Re: Easy Puzzles
« Reply #421 on: September 05, 2013, 11:02:46 pm »
0

Maybe too easy:
You lost Duchy split 1-7. At the end of the game your Dukes are worth 3 points. How is that possible?
Two technically correct answers:
-You have no Dukes (so all of them are worth 3 points)
-You have 1 Duke, which also exactly increases the value of your 2 Silk Road, so in some sense, the Duke is worth 3 points.

Neither is technically correct.  If you have no Dukes, your Dukes are not worth anything.  If you have 1 Duke and 2 SR, the Duke itself would still be worth X equal to the number of Duchies you have; the increase in value of SR is the worth of the SR, not the Duke.

A technically correct answer would be -- you have 3 Dukes.  With 1 Duchy, 3 Dukes are worth 3 points.  (The question did not say that the Dukes were worth 3 points each.)

The first one can work, depending on your definition of  "your dukes are worth 3 points," if taken to mean "if a duke is in your deck, it is worth 3 points"  then if you don't have any dukes in your deck you have a contradiction and can derive anything.

Edit: Ninja'd (and I really shouldn't be surprised).

I understand the logic involved, but the value of Dukes are clearly defined.
The definition of Duke's value is irrelevant if there are no Dukes in your deck.

I could say both "All of the turtles I have ever owned are alive" and "All of the turtles I have ever owned are dead" and be completely correct in both cases because I have never owned a turtle.  If there are no Dukes in your deck, then all of the dukes in your deck are worth 3 points, even if it's the case that if you would have had a Duke it would have been worth 1 point.  The only argument I can think of against that solution would be to say that the statement "your Dukes are worth 3 points" implies that you have at least one Duke, although I don't think it does.
« Last Edit: September 05, 2013, 11:03:48 pm by scott_pilgrim »
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eHalcyon

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Re: Easy Puzzles
« Reply #422 on: September 05, 2013, 11:11:06 pm »
0

I'd say that the statement, "your Dukes are worth 3 points" technically and literally says that the combined VP value of your Dukes is 3 points, which means that you CANNOT have 0 Dukes.  From the given "correct" answer, that wasn't the meaning meant, but that means the problem was incorrectly stated. ;)
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scott_pilgrim

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Re: Easy Puzzles
« Reply #423 on: September 05, 2013, 11:14:46 pm »
0

I'd say that the statement, "your Dukes are worth 3 points" technically and literally says that the combined VP value of your Dukes is 3 points, which means that you CANNOT have 0 Dukes.  From the given "correct" answer, that wasn't the meaning meant, but that means the problem was incorrectly stated. ;)
Ah, I guess that is another fair argument against that solution then.  I interpreted it as "each of your Dukes is worth 3 points" rather than "all of your Dukes (together) are worth 3 points".  Actually now that I think about it, the latter seems more like the technically correct interpretation, but the original post is ambiguous either way I think.
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Witherweaver

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Re: Easy Puzzles
« Reply #424 on: September 06, 2013, 09:16:40 am »
+1

Maybe too easy:
You lost Duchy split 1-7. At the end of the game your Dukes are worth 3 points. How is that possible?
Two technically correct answers:
-You have no Dukes (so all of them are worth 3 points)
-You have 1 Duke, which also exactly increases the value of your 2 Silk Road, so in some sense, the Duke is worth 3 points.

Neither is technically correct.  If you have no Dukes, your Dukes are not worth anything.  If you have 1 Duke and 2 SR, the Duke itself would still be worth X equal to the number of Duchies you have; the increase in value of SR is the worth of the SR, not the Duke.

A technically correct answer would be -- you have 3 Dukes.  With 1 Duchy, 3 Dukes are worth 3 points.  (The question did not say that the Dukes were worth 3 points each.)

The first one can work, depending on your definition of  "your dukes are worth 3 points," if taken to mean "if a duke is in your deck, it is worth 3 points"  then if you don't have any dukes in your deck you have a contradiction and can derive anything.

Edit: Ninja'd (and I really shouldn't be surprised).

That's not a contradiction.  The statement "If a Duke is in your deck, it is worth three points" is vacuously true in the case that there are zero Dukes in your deck.  The statement is satisfied because in every case when the hypothesis is satisfied, the conclusion is satisfied.
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