Topic: Break the Code - Forum Version (Read 11580 times)

Jimmmmm · « **Reply #50 on:** June 21, 2022, 10:49:32 pm »

I won't include the rightmost one in my notes.

EFHW · « **Reply #51 on:** June 21, 2022, 10:57:33 pm »

Quote from: Jimmmmm on June 21, 2022, 10:49:32 pm

I won't include the rightmost one in my notes.

It's ok, my mistake

infangthief · « **Reply #52 on:** June 22, 2022, 01:26:28 am »

Quote from: Jimmmmm on June 21, 2022, 06:45:34 pm

What is the sum of your 3 leftmost tiles?

15

EFHW · « **Reply #53 on:** June 22, 2022, 08:47:19 am »

I am ready to guess.

Jimmmmm · « **Reply #54 on:** June 22, 2022, 08:50:51 am »

You just note it down and look, right?

EFHW · « **Reply #55 on:** June 22, 2022, 08:52:17 am »

I got it right.

Since I went first, each of you gets a chance to guess the answer and win with me. Or you can ask a question and play for second.

PPE Jimmmmm: Right

EFHW · « **Reply #56 on:** June 22, 2022, 08:55:30 am »

fang's turn

infangthief · « **Reply #57 on:** June 22, 2022, 09:46:54 am »

Ok, I'm guessing also.

infangthief · « **Reply #58 on:** June 22, 2022, 09:49:19 am »

I got it right too.

Jimmmmm?

Jimmmmm · « **Reply #59 on:** June 22, 2022, 09:50:01 am »

Something's not adding up for me.

Jimmmmm · « **Reply #60 on:** June 22, 2022, 10:19:23 am »

Before checking...

I have W0 | B2 | B3 | B4 | G5.

EFHW has a total of 28 and a | b | c sum is 10, therefore d | e sum is 18, which can only be B9 | W9.
c | d is consecutive but different colours, so must have ? | ? | W8 | B9 | W9.
a | b sum is therefore 2, and b | c are same colour, leaving B0 | W2 | W8 | B9 | W9 or B1 | W1 | W8 | B9 | W9.

fang's c | d are the same colour. They can't be 5G as I have one. e can't be 5G as there is no X | Y | X | X combination less than 5. a can't be 5G as a | b | c would sum to at least 17.
If b is 5G then a and c must sum to 10. c can't be 7 as that would require a higher W, so it must be 4W | 5G | 6W | 7W | 8B, but the difference between the e and the a is only 4, so b can't be 5G, so we have all B and W.
Only two B so it must be W | B | W | W | B. But that doesn't work because the first B must be at least 6, and there's no W higher than 7.

So something somewhere has gone wrong it seems.

Jimmmmm · « **Reply #61 on:** June 22, 2022, 10:27:42 am »

Alright so EFHW is B0 | W2 | W8 | B9 | W9 as expected.

fang is W3 | B6 | W6 | W7 | B8.

Ah yes so I was overlooking the possibility of b | c being the same number. Other than that I don't seem to have enough information to distinguish between the two possibilities for EFHW.

infangthief · « **Reply #62 on:** June 22, 2022, 10:29:13 am »

I also didn't have enough info to distinguish between the two possibilities for EFHW... except that one of them gave her enough info to guess with certainty and the other she'd have only had a 33% chance of being right. So I assumed the former.

infangthief · « **Reply #63 on:** June 22, 2022, 10:33:43 am »

Good game though, it is amazing how quickly the info all comes together.

Jimmmmm · « **Reply #64 on:** June 22, 2022, 10:34:42 am »

Quote from: infangthief on June 22, 2022, 10:33:43 am

Good game though, it is amazing how quickly the info all comes together.

Ah yes I would have gone into that thought process if I was actually trying to get the answer.

Jimmmmm · « **Reply #65 on:** June 22, 2022, 10:35:24 am »

Quote from: Jimmmmm on June 22, 2022, 10:34:42 am

Quote from: infangthief on June 22, 2022, 10:29:13 am
I also didn't have enough info to distinguish between the two possibilities for EFHW... except that one of them gave her enough info to guess with certainty and the other she'd have only had a 33% chance of being right. So I assumed the former.

Ah yes I would have gone into that thought process if I was actually trying to get the answer.

FTFM

Jimmmmm · « **Reply #66 on:** June 22, 2022, 10:38:55 am »

I'd play again. It seemed quite quick, which is probably a good thing IRL, but in this format it might be interesting to try using more tiles and longer codes?

I feel like having 4 consecutive numbers made mine very easy to get. My choice of questions, particularly my first one, was intended to take away what would be most useful in further clearing up my hand.

infangthief · « **Reply #67 on:** June 22, 2022, 10:53:00 am »

Yes, my double-6 meant that your run of 4 gave me lots of info. But once you'd chosen that colour question, it was hard for me to find out anything more, because all the other questions were about numbers.

EFHW · « **Reply #68 on:** June 22, 2022, 12:57:28 pm »

yeah, you guys caught on quickly! I picked the high-low question to obfuscate my first and last numbers.

Fang, are you in again? I think Swowl wants to play, and we can see if 4 person is more challenging than 3. Let's continue with asker doesn't reveal their info.

EFHW · « **Reply #69 on:** June 22, 2022, 12:58:30 pm »

Quote from: Jimmmmm on June 22, 2022, 10:38:55 am

I'd play again. It seemed quite quick, which is probably a good thing IRL, but in this format it might be interesting to try using more tiles and longer codes?

I feel like having 4 consecutive numbers made mine very easy to get. My choice of questions, particularly my first one, was intended to take away what would be most useful in further clearing up my hand.

Yeah, the 4 consecutive numbers did take me a very long way.

EFHW · « **Reply #70 on:** June 22, 2022, 01:01:31 pm »

another way to make it harder would be to not have tiles of our own.

EFHW · « **Reply #71 on:** June 22, 2022, 01:04:00 pm »

Quote from: EFHW on June 22, 2022, 01:01:31 pm

another way to make it harder would be to not have tiles of our own.

Well, one person could play that way as spectator.

infangthief · « **Reply #72 on:** June 22, 2022, 02:14:19 pm »

/inagain

infangthief · « **Reply #73 on:** June 23, 2022, 12:07:44 am »

Actually I'd better sit out for a round, as I'm VLA next week and there seems a reasonable chance it wouldn't finish until then.

infangthief · « **Reply #74 on:** August 15, 2022, 03:32:42 am »

Can we play again?

EFHW, Jimmm, anyone else?

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Author Topic: Break the Code - Forum Version (Read 11580 times)