e, two things:

1. The opponent would not be able to have 33 VPs by having 7 provinces and 9 curses.

2. The 10 Alchemists will draw you more than 10 cards in total.

Awaclus:

I don't know why the player would have bought 9 curses themselves either, but I do suppose with the way I worded the puzzle, it would be a possibility. I hadn't intended for that to be an option (I suppose you could have bought all 9 curses and intentionally not played any Familiars you had drawn in previous turns...), so good catch! If you assume the opponent has the 9 curses and all Provinces, as far as I can tell, the one and only one hand you could draw that would not let you win the game is what you said, 4 Vineyards, 9 Transmutes, and 2 Universities. Using the mathematical equation for combinations, we can find the maximum likelihood of that scenario as one over the total combinations of 15 card hands out of a deck of 26 (the minimum number of cards you could have in the puzzle, if you bought anything extra (like extra golds), the odds are even less likely). The total number of combinations are = 26!/(15!11!) = 7,726,160. So, one out of every 7.7 billion times you are placed in this situation, you will be unable to win.