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Messages - pacovf

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4501
General Discussion / Re: A joke thread
« on: January 27, 2013, 05:18:18 pm »
If you are into obscure music jokes, I suggest Don't Shoot the Pianist.

e.g. http://euge.ca/2012/09/16/birthday/
http://euge.ca/2012/05/18/octave/
http://euge.ca/2012/05/04/three-hands/
http://euge.ca/2012/01/13/interruption/

Out of curiosity, for those of us that never took solfège lessons, which... err... scores (?) are played in "octave" you linked to, and in "coping" (http://euge.ca/2011/12/23/coping/) ?

4502
General Discussion / Re: Logic problems
« on: January 22, 2013, 07:34:08 pm »
If any of you lack the capacity to solve problems involving infinitely countable hats (I know I do), here's one of my favourite puzzles (this one is by Raymond Smullyan; I had to retranslate the version I have, so sorry if the English is wonky):

In 1918, the day the First World War armistice was signed, three married couples celebrated the occasion dining together. Each husband is the brother of one wife, and each wife is the sister of one husband; that is, there are three brother-sister pairs in the group. We know the following:

-Helen is exactly twenty-six weeks older than her husband, who was born in august.
-The sister of Mr. White, who is married to the brother-in-law of Helen’s brother, got married to him on her birthday, which is in January.
-Marguerite White isn’t as tall as William Black.
-Arthur’s sister is taller than Beatrice.
-John is fifty years old.

What is Mrs. Brown first name?

I don't know if anyone will try to solve this one or not, but just in case, here's a hint that normally should get you to the answer:
The date is relevant.

4503
General Discussion / Re: Logic problems
« on: January 17, 2013, 06:37:55 pm »
I think it would be a lot faster to have the maiden who goes into the tower Day 1 to set the switch in the proper off position.

A witch captures 50 maidens. She puts them all in a dungeon and tells them: "Tomorrow morning I will separate you into 50 separate cells, so you will not be able to communicate or see each other in any way after tonight. Then every once in a while, a few times a day or so, I will randomly choose one of you and take you to my tower.

The information isn't exact enough that you can do that.  I don't think it is guaranteed that any of them will be taken the first day.  Depends on how you read the problem, I guess.

That's the problem: no maid can be sure that she's the first to be taken to the switch room.

4504
General Discussion / Re: Logic problems
« on: January 17, 2013, 04:11:18 pm »
You are globally right, yes. The end of the puzzle is somewhat more subtle though.

4505
General Discussion / Re: Logic problems
« on: January 16, 2013, 01:50:00 pm »
Helen

I'll wait for the spoilered explanation since, you know, there's a 50% chance to guess randomly :)

4506
General Discussion / Re: Logic problems
« on: January 16, 2013, 01:40:33 pm »
If any of you lack the capacity to solve problems involving infinitely countable hats (I know I do), here's one of my favourite puzzles (this one is by Raymond Smullyan; I had to retranslate the version I have, so sorry if the English is wonky):

In 1918, the day the First World War armistice was signed, three married couples celebrated the occasion dining together. Each husband is the brother of one wife, and each wife is the sister of one husband; that is, there are three brother-sister pairs in the group. We know the following:

-Helen is exactly twenty-six weeks older than her husband, who was born in august.
-The sister of Mr. White, who is married to the brother-in-law of Helen’s brother, got married to him on her birthday, which is in January.
-Marguerite White isn’t as tall as William Black.
-Arthur’s sister is taller than Beatrice.
-John is fifty years old.

What is Mrs. Brown first name?

4507
General Discussion / Re: DominionStrategy Forum Members Map!
« on: January 14, 2013, 06:34:42 pm »
Oops, forgot to mention that this is probably late March - early April.  The plan was to see Barca v Mallorca, which I gather is not a particularly 'hot' match.  When should I buy those tickets?  Where should I sit in Camp Nou?  Is there any concern that Barca fields a team of B players, so that I don't actually get to see Messi/Iniesta/etc.?

My Spanish is poor.  My wife's is much better, but mostly Latin American.  I'm going to get ready to hear a lot of "Ethh-pañol" :-)

Finally, the plan is to visit Sevilla and/or Granada.  No set plan -- any recommendations?  (Other than delicious sangria)

I can't really give you any piece of advice about which seat you should get, since I've never been to a game myself (I'm not really into football); however, one third of the tickets have already been sold for the Barça-Mallorca, so I wouldn't wait much longer to get them either.

About Sevilla and Granada, if you can only go to one of them, go to Sevilla, there are more things to do there; however, you'll be losing on the Alhambra... I can't really go into much detail about them, since I've seldom been there.

4508
General Discussion / Re: DominionStrategy Forum Members Map!
« on: January 14, 2013, 03:35:36 pm »
As far as I know and according to their official site, only three games take place that month at the Camp Nou: Barça-Deportivo de la Coruña (10/03/13), Barça-Milan (12/03/2013) and Barça-Rayo Vallecano (17/03/2013). We are talking 20-80€ for the Rayo Vallecano, but 80€-160€ to see the Milan (that's expected to be a very good game, in case it wasn't obvious); there aren't many seats left, so if that's when you are going, buy the tickets now before it's too late!

About the city itself, well, obviously the two most visited landmarks are the Camp Nou (AKA the Catalan Mecca) and the Sagrada Familia (make sure to get inside, by the way, it's definitely worth the standing line); aside from that, you want to visit the "Barri Gotic" (old city center, beware the pickpockets), las Ramblas (beware the pickpockets there too) and "Passeig de Gràcia" (the most recognizable XIXth century Barcelona), anything else signed by Gaudi (at the very least you've got the "Parc Güell" left, that isn't negotiable). Then it depends on how much time you've got and the kind of things that you want to see, but the Port is nice and there's plenty of thing to do there; so is the Tibidabo (one of the hills that surround BCN), which among other things holds a 112 year old amusement park; Montjuic (with, among other things, the "Palau Nacional", AKA Catalan National Art Museum).

And in case you didn't know, most people only grudgingly speak Spanish in Barcelona, they rather speak Catalan here. On the other hand, Andalucian accent is pretty rough too, so if you were planning to improve your Spanish, tough luck :)

Where to Andalucía, by the way? Córdoba, Sevilla, Granada...?

4509
General Discussion / Re: Logic problems
« on: January 14, 2013, 06:35:47 am »
I guess you cannot give a clue to those of us that are clueless...?

I cannot fathom how:
-Infinite people discuss a strategy;
-Devil puts hats on people according to the strategy they have agreed upon;
-Without any means to communicate (since they have to shout simultaneously, which negates the possibility that waiting "t" seconds before shouting means anything) after the hats are on, they have to guess the colour of their hat;

can somehow lead to a finite amount of errors. Afterall, the impossibility to communicate once the hats are on means that they cannot react to the devil's strategy, while the devil can react to their strategy, which would mean that their best shot at surviving would be to guess randomly...

4510
General Discussion / Re: DominionStrategy Forum Members Map!
« on: January 14, 2013, 06:30:21 am »
I'm planning to visit Barcelona in March.  Any advice?  :)

Nice! How long will you stay here? General advice, or places to visit?

4511
General Discussion / Re: DominionStrategy Forum Members Map!
« on: January 13, 2013, 07:10:14 am »
I was surprised to be the only one in Barcelona, but turns out I'm the only one in the whole Iberian Peninsula.
We've got nice warm weather here, I guess that's why people would rather be outside. I am so lonely... [cue Lonely by Akon... yes, I am a very sad person]

4512
Dominion General Discussion / Re: How much of dominion skill is luck?
« on: January 13, 2013, 06:16:51 am »
In this particular case, more of the issue is that you perceive Gold as being a step ahead of the 5$ cards, and often it's not.

Though, sometimes, in base set, it is.  If you get expansion, Dominion rapidly becomes a more skill-based game.

I wouldn't go as far as saying that "Gold often isn't a step ahead of the 5$ cards". Aside from cursers, there aren't that many 5$ cards that you would rather have than a gold, pre-third shuffle, since it's "usually" too early to have a combo built. A gold all but guarantees that you will get that 5$ card that you wanted before your next reshuffle, but a 5$ card doesn't guarantee a gold, and there aren't that many strategies that don't rely on getting one or two of them.

4513
General Discussion / Re: Logic problems
« on: January 13, 2013, 04:29:29 am »
I'd put the order of priorities of pirates this way:
-Survive
-Earn as much money as possible
-Kill as many pirates as possible

So, in the case that pirates are perfectly trustworthy, a follow-up to Titandrake's post:

[EDIT: actually, it doesn't work; I'm still thinking on it, but I forgot that in a 4 crew ship, any deal that doesn't involve the captain requires all other pirates to agree, so that they represent the majority]
-With 4 pirates, if no promise is made, the second pirate will accept whatever the captain offers, 0 coins included, or otherwise he will die, as Titandrake said.
However, the third pirate can strike a pact with the second pirate: if he votes against the captain, he will accept a 0, 100, 0 split afterwards, which the second pirate and fourth pirate would normally accept, since that way they kill one extra pirate; but the fourth pirate can also offer a 0,0,100 split, which is equivalent for the second captain; as such, they will both rise their offers until they both reach 99 coins for the second pirate and one coin for the relevant pirate, so that doesn't seem like a very good split for the third or fourth pirates. Assuming (*), this means a 99, 1, 0 split.
Thus, the captain (a bit nervous since everybody is discussing his death) will instead try to earn the loyalty of the third or fourth pirate, and one coin for the fourth pirate should suffice , since otherwise he would earn nothing. But! Whatever 100-n, 0, 0 n split the captain proposes, the second pirate can offer the same to either the third or fourth pirate, and they will accept, since they are bloodthirsty. As such, the captain, trying to survive, will offer the 100 coins to either the third or fourth pirate, and the second pirate, seeing that he will earn nothing, will also offer 100 coins to either the third or fourth pirate, as he is bloodthirsty.
Probably before reaching that point, the captain and the second in command will realize that it may be better to reach an agreement between them, but that's prisoner dilemma: if the captain offers a 100-n, n, 0, 0 split, the second pirate could accept, or try to get a better deal with either the third or fourth pirate, which is always possible, since a 0, n, 0, 100-n split seems better for him (he gets to kill the captain); but that reasoning leads to a 0, 0, 0, 100 split (according to the previous paragraph), which is worse than the previous 100-n, n, 0, 0 split...


Adding extra rules about how and when the pirates can strike a deal would make this quite easier... or solvable...

*I would add that, if a pirate has the choice among more than one deal that are equivalent to him (according to the three laws of buccaneering above), he will choose the one proposed by the highest ranking pirate. It can shave some lines of discussion for higher number of pirates.

4514
General Discussion / Re: Logic problems
« on: January 12, 2013, 10:35:05 am »
Captain keeps 97 for himself and gives 1 to each of 3, 5 and 7?

Yep! Obviously, if the pirates could leave the ship, I'm sure that wouldn't be the solution :)

Does the captain get a vote? I forget.

Figured this one out. Yeah, cap gets a vote too, checked wiki for exact setup. Also, they want as much money as they can get (greedy), and if they can kill some other pirate while still receiving the same amount of money, the will do so (bloodthirsty).

Ah, you beat me :)

You can solve the problem too if the captain doesn't get a vote; it's slightly harder, and gets you a different result, but the way you get the solution is the same.

4515
General Discussion / Re: Logic problems
« on: January 12, 2013, 06:04:43 am »
My favorite puzzles have already been posted (blue eyes, 100 prisoners), so I'll just post a somewhat easy one:

7 pirates have just ended plundering the Caribbean, so they get together to discuss how they will share the 100 gold coin booty. Now, these aren't your normal kind of pirates, they are blood-thirsty, unlimitedly greedy, perfectly rational pirates, and they are ranked by fighting prowess.

Thus, the captain has to propose how to share the booty, knowing that if more than half of his crew starts a mutiny, he will get killed, and the 2nd in command will take his place (who will in turn have to propose how to share the booty, eventually being replaced by the third in command, etc.).

How much gold will each pirate receive?

4516
General Discussion / Re: Probability paradoxes
« on: January 10, 2013, 06:49:28 am »
Quote
I have one sibling.  At least one of us is a boy.  What is the probability that the other is also a boy?

In this case, knowing that at least one of you two is a boy leaves three possibilities for you/sibling:

boy/boy
boy/girl
girl/boy

And now we have 2/3 male sibling.

Maybe I'm just being dense, but how do we know that these three possibilities are equally probable? The knowledge that there is at least one boy affects the possible outcomes (girl/girl isn't possible), so why wouldn't it also affect the probability of each one?

4517
If there is one DA card and one prosperity card, the odds of getting both shelters and colonies are:
-1/100 when shuffling a second time;
-1/90 when using the top/bottom technique.

Not really intuitive, but that's how it is.

4518
Other Games / Re: So Pokemon X and Y.
« on: January 09, 2013, 06:03:21 pm »
I agree that a type change would be nice, but Fighting/Psychic/Dark isn't balanced because Dark is not just resistant to Psychic but fully immune.  A workable triangle would be Fighting/Rock/Flying.  Two more are Fire/Rock/Steel and Grass/Poison/Ground, but those dip into the original three.  There aren't any triangles other than these, I think.

Here's the list of all the imperfect triangles, id.est., A is very effective against B, B is very effective against C, C is very effective against A. Took me a while to find it out, I'm sure it has been done already, but oh well:
-fire/grass/water
-fire/ice/ground
-fire/steel/rock
-fire/grass/rock
-fire/grass/ground
-water/ground/electric (immunity)
-grass/ground/poison
-grass/rock/ice
-ice/flying/fighting
-grass/rock/flying
-ice/ground/rock
-ice/ground/steel
-grass/rock/flying
-grass/rock/bug
-fighting/rock/flying
-fighting/dark/psychic (immunity)

If you also want to have A is very resistant against B, B is very resistant against C, C is very resistant against A, then you are left with only:
-fire/grass/water
-fire/steel/rock
-grass/ground/poison
-fighting/rock/flying

So, if you don't want to repeat any type, fighting-rock-flying it is!

EDIT: this gets more difficult with dual types. If I was bored enough, I could write a small script to find perfect dual-type triangles, but you know...

4519
Puzzles and Challenges / Re: Ruined Palace
« on: December 16, 2012, 12:39:33 pm »
Actually, you need 88 plays of abandoned mine, and 7 plays of ruined market, and enough king's court/throne room/ruined library to support them.

Chaining King Courts provides 2*n-1 effective plays of King Courts for one action. King courting a throne room provides 6 plays of the card in question, but requires three copies of the card and the throne room, instead of one; so, its only benefit is allowing a division of the multiplied actions, but it's just as good/bad from a card draw perspective. Maybe you can dig this to find a solution with more throne rooms and less king courts?*

Anyway, we need one king courted ruined market and two throne roomed; 28 king courted abandoned mines, and two throne roomed. That means two king courted throne rooms (and we are left with two uses of throne room to spare), so 48 (16 of which are king courts) cards to draw. Two king courted ruined libraries provide six cards, and costs three cards (the king court, with one use left for the next one; and the two ruined libraries), for a net gain of three cards. Since we have to draw 43 cards (48, minus the 5 you start with), and we had two spare throne rooms (the first applied on a ruined library, the second on a king court applied on two libraries), the end result is the need to draw 39 cards, so that means another 13 (+1) king courts, and 26 (+3) ruined libraries, and no card draw left.


End result:
-30 king courts
-2 throne rooms
-29 ruined libraries
-28 abandoned mines
-3 ruined markets


And no spare buy/coin/card draw.
*Fast thinking: normally, once your king court chain is going, you would do king court (ruined library; ruined library; king court (abandoned mine; abandoned mine; REPEAT), which draws itself (6 cards) and provides 6 coin for two king courts.
Instead, you could do king court (ruined library; ruined library; king court (ruined library; ruined library; king court (ruined library; ruined library; king court (throne room (abandoned mine; abandoned mine; abandoned mine); throne room (abandone mine; abandoned mine; abandoned mine); REPEAT))); which draws itself (18 cards), and provides 12 coins for four king courts and two throne rooms, so you're worse than in the first case;

So I'm pretty sure I got the best answer.


Man, I sure love procrastinating :P

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